Base | Representation |
---|---|
bin | 11101110010111011101100… |
… | …000001100001010100000111 |
3 | 122011222121221200210221202100 |
4 | 131302323230001201110013 |
5 | 114134003401434210120 |
6 | 1142412302402443143 |
7 | 36413400624441045 |
oct | 3562735401412407 |
9 | 564877850727670 |
10 | 131043412022535 |
11 | 388332208791a1 |
12 | 128451116634b3 |
13 | 581745777840c |
14 | 245076bdcd395 |
15 | 1023b17126490 |
hex | 772eec061507 |
131043412022535 has 48 divisors (see below), whose sum is σ = 228878960289408. Its totient is φ = 69355358654400.
The previous prime is 131043412022533. The next prime is 131043412022573. The reversal of 131043412022535 is 535220214340131.
131043412022535 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 43 + 41 + 20 + 22 + 535 = 666.
It is not a de Polignac number, because 131043412022535 - 21 = 131043412022533 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131043412022535.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131043412022533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 712088844 + ... + 712272846.
It is an arithmetic number, because the mean of its divisors is an integer number (4768311672696).
Almost surely, 2131043412022535 is an apocalyptic number.
131043412022535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131043412022535 is a deficient number, since it is larger than the sum of its proper divisors (97835548266873).
131043412022535 is a wasteful number, since it uses less digits than its factorization.
131043412022535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 304956 (or 304953 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 131043412022535 its reverse (535220214340131), we get a palindrome (666263626362666).
The spelling of 131043412022535 in words is "one hundred thirty-one trillion, forty-three billion, four hundred twelve million, twenty-two thousand, five hundred thirty-five".
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