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13104343244033 is a prime number
BaseRepresentation
bin1011111010110001011110…
…1110010101110100000001
31201101202121012201112021022
42332230113232111310001
53204200143332302113
643512015134235225
72521520561502056
oct276542756256401
951352535645238
1013104343244033
1141a258014a378
121577862055b15
13740971248632
14334379c2902d
1517ad19d48908
hexbeb17b95d01

13104343244033 has 2 divisors, whose sum is σ = 13104343244034. Its totient is φ = 13104343244032.

The previous prime is 13104343243993. The next prime is 13104343244039. The reversal of 13104343244033 is 33044234340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9817838355649 + 3286504888384 = 3133343^2 + 1812872^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104343244033 - 236 = 13035623767297 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104343243984 and 13104343244002.

It is not a weakly prime, because it can be changed into another prime (13104343244039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552171622016 + 6552171622017.

It is an arithmetic number, because the mean of its divisors is an integer number (6552171622017).

Almost surely, 213104343244033 is an apocalyptic number.

It is an amenable number.

13104343244033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104343244033 is an equidigital number, since it uses as much as digits as its factorization.

13104343244033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 13104343244033 its reverse (33044234340131), we get a palindrome (46148577584164).

The spelling of 13104343244033 in words is "thirteen trillion, one hundred four billion, three hundred forty-three million, two hundred forty-four thousand, thirty-three".