Base | Representation |
---|---|
bin | 1011111010110001011110… |
… | …1110010101110100000111 |
3 | 1201101202121012201112021112 |
4 | 2332230113232111310013 |
5 | 3204200143332302124 |
6 | 43512015134235235 |
7 | 2521520561502065 |
oct | 276542756256407 |
9 | 51352535645245 |
10 | 13104343244039 |
11 | 41a258014a383 |
12 | 1577862055b1b |
13 | 740971248638 |
14 | 334379c29035 |
15 | 17ad19d4890e |
hex | beb17b95d07 |
13104343244039 has 2 divisors, whose sum is σ = 13104343244040. Its totient is φ = 13104343244038.
The previous prime is 13104343244033. The next prime is 13104343244053. The reversal of 13104343244039 is 93044234340131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104343244039 - 240 = 12004831616263 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13104343243987 and 13104343244005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104343244033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552171622019 + 6552171622020.
It is an arithmetic number, because the mean of its divisors is an integer number (6552171622020).
Almost surely, 213104343244039 is an apocalyptic number.
13104343244039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104343244039 is an equidigital number, since it uses as much as digits as its factorization.
13104343244039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248, while the sum is 41.
The spelling of 13104343244039 in words is "thirteen trillion, one hundred four billion, three hundred forty-three million, two hundred forty-four thousand, thirty-nine".
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