Base | Representation |
---|---|
bin | 11101110010111011101110… |
… | …010111001000001111110011 |
3 | 122011222122001102121111000002 |
4 | 131302323232113020033303 |
5 | 114134003442004211314 |
6 | 1142412310323220215 |
7 | 36413401612003661 |
oct | 3562735627101763 |
9 | 564878042544002 |
10 | 131043451241459 |
11 | 38833240a25a29 |
12 | 1284512281766b |
13 | 581746292a593 |
14 | 24507732bbc31 |
15 | 1023b1a7c1ade |
hex | 772eee5c83f3 |
131043451241459 has 2 divisors, whose sum is σ = 131043451241460. Its totient is φ = 131043451241458.
The previous prime is 131043451241387. The next prime is 131043451241471. The reversal of 131043451241459 is 954142154340131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131043451241459 is a prime.
It is a super-2 number, since 2×1310434512414592 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131045451241459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521725620729 + 65521725620730.
It is an arithmetic number, because the mean of its divisors is an integer number (65521725620730).
Almost surely, 2131043451241459 is an apocalyptic number.
131043451241459 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043451241459 is an equidigital number, since it uses as much as digits as its factorization.
131043451241459 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1036800, while the sum is 47.
The spelling of 131043451241459 in words is "one hundred thirty-one trillion, forty-three billion, four hundred fifty-one million, two hundred forty-one thousand, four hundred fifty-nine".
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