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131043881 is a prime number
BaseRepresentation
bin1111100111110…
…01001000101001
3100010120201102002
413303321020221
5232021401011
621000420345
73150566063
oct763711051
9303521362
10131043881
1167a75231
1237a776b5
13211c2977
1413592733
15b787c3b
hex7cf9229

131043881 has 2 divisors, whose sum is σ = 131043882. Its totient is φ = 131043880.

The previous prime is 131043877. The next prime is 131043883. The reversal of 131043881 is 188340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104366656 + 26677225 = 10216^2 + 5165^2 .

It is a cyclic number.

It is not a de Polignac number, because 131043881 - 22 = 131043877 is a prime.

It is a super-2 number, since 2×1310438812 = 34344997495084322, which contains 22 as substring.

Together with 131043883, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131043883) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521940 + 65521941.

It is an arithmetic number, because the mean of its divisors is an integer number (65521941).

Almost surely, 2131043881 is an apocalyptic number.

It is an amenable number.

131043881 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043881 is an equidigital number, since it uses as much as digits as its factorization.

131043881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 29.

The square root of 131043881 is about 11447.4399321420. The cubic root of 131043881 is about 507.9320090562.

The spelling of 131043881 in words is "one hundred thirty-one million, forty-three thousand, eight hundred eighty-one".