1310440141 has 2 divisors, whose sum is σ = 1310440142. Its totient is φ = 1310440140.

The previous prime is 1310440133. The next prime is 1310440147. The reversal of 1310440141 is 1410440131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 818532100 + 491908041 = 28610^2 + 22179^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310440141 - 2³ = 1310440133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310440147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655220070 + 655220071.

It is an arithmetic number, because the mean of its divisors is an integer number (655220071).

Almost surely, 2^1310440141 is an apocalyptic number.

It is an amenable number.

1310440141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310440141 is an equidigital number, since it uses as much as digits as its factorization.

1310440141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 1310440141 is about 36200.0019475138. The cubic root of 1310440141 is about 1094.3067109802.

Adding to 1310440141 its reverse (1410440131), we get a palindrome (2720880272).

The spelling of 1310440141 in words is "one billion, three hundred ten million, four hundred forty thousand, one hundred forty-one".