Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …0000011001001100110111 |
3 | 1201101202202100020011112200 |
4 | 2332230123100121030313 |
5 | 3204200304020034310 |
6 | 43512025052315543 |
7 | 2521522211260125 |
oct | 276543320311467 |
9 | 51352670204480 |
10 | 13104402502455 |
11 | 41a2600644080 |
12 | 1577879a72bb3 |
13 | 7409805c5ba4 |
14 | 334383a52915 |
15 | 17ad201519c0 |
hex | beb1b419337 |
13104402502455 has 96 divisors (see below), whose sum is σ = 25038639924480. Its totient is φ = 6287156029440.
The previous prime is 13104402502447. The next prime is 13104402502519. The reversal of 13104402502455 is 55420520440131.
13104402502455 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 402 + 5 + 0 + 245 + 5 = 666.
It is not a de Polignac number, because 13104402502455 - 23 = 13104402502447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 370802176 + ... + 370837514.
It is an arithmetic number, because the mean of its divisors is an integer number (260819165880).
Almost surely, 213104402502455 is an apocalyptic number.
13104402502455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13104402502455 is a deficient number, since it is larger than the sum of its proper divisors (11934237422025).
13104402502455 is a wasteful number, since it uses less digits than its factorization.
13104402502455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43181 (or 43178 counting only the distinct ones).
The product of its (nonzero) digits is 96000, while the sum is 36.
Adding to 13104402502455 its reverse (55420520440131), we get a palindrome (68524922942586).
The spelling of 13104402502455 in words is "thirteen trillion, one hundred four billion, four hundred two million, five hundred two thousand, four hundred fifty-five".
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