Base | Representation |
---|---|
bin | 111101000001011010… |
… | …1010100001001110101 |
3 | 110112020200110121211221 |
4 | 1322002311110021311 |
5 | 4121334233030031 |
6 | 140111212230341 |
7 | 12316251621520 |
oct | 1720265241165 |
9 | 415220417757 |
10 | 131044033141 |
11 | 50636a3873a |
12 | 2149246b3b1 |
13 | c48528b218 |
14 | 64b1dd9bb7 |
15 | 361e841a11 |
hex | 1e82d54275 |
131044033141 has 4 divisors (see below), whose sum is σ = 149764609312. Its totient is φ = 112323456972.
The previous prime is 131044033121. The next prime is 131044033151. The reversal of 131044033141 is 141330440131.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131044033141 - 223 = 131035644533 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131044033121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9360288075 + ... + 9360288088.
It is an arithmetic number, because the mean of its divisors is an integer number (37441152328).
Almost surely, 2131044033141 is an apocalyptic number.
It is an amenable number.
131044033141 is a deficient number, since it is larger than the sum of its proper divisors (18720576171).
131044033141 is an equidigital number, since it uses as much as digits as its factorization.
131044033141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18720576170.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 131044033141 its reverse (141330440131), we get a palindrome (272374473272).
The spelling of 131044033141 in words is "one hundred thirty-one billion, forty-four million, thirty-three thousand, one hundred forty-one".
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