Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …1010110110010110110010 |
3 | 1201101202202112101102021222 |
4 | 2332230123122312112302 |
5 | 3204200310220241224 |
6 | 43512025231145042 |
7 | 2521522243464020 |
oct | 276543332662662 |
9 | 51352675342258 |
10 | 13104405243314 |
11 | 41a2602146350 |
12 | 157787a975182 |
13 | 7409810455b8 |
14 | 334384167710 |
15 | 17ad204e3b5e |
hex | beb1b6b65b2 |
13104405243314 has 64 divisors (see below), whose sum is σ = 25273331251200. Its totient is φ = 4948385164800.
The previous prime is 13104405243313. The next prime is 13104405243367. The reversal of 13104405243314 is 41334250440131.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13104405243313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9511679 + ... + 10801890.
It is an arithmetic number, because the mean of its divisors is an integer number (394895800800).
Almost surely, 213104405243314 is an apocalyptic number.
13104405243314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13104405243314 is a deficient number, since it is larger than the sum of its proper divisors (12168926007886).
13104405243314 is a wasteful number, since it uses less digits than its factorization.
13104405243314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20313719.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 13104405243314 its reverse (41334250440131), we get a palindrome (54438655683445).
The spelling of 13104405243314 in words is "thirteen trillion, one hundred four billion, four hundred five million, two hundred forty-three thousand, three hundred fourteen".
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