13104411014020 has 48 divisors (see below), whose sum is σ = 27710384083200. Its totient is φ = 5205485736320.

The previous prime is 13104411013943. The next prime is 13104411014033. The reversal of 13104411014020 is 2041011440131.

It is a junction number, because it is equal to n+sod(n) for n = 13104411013982 and 13104411014000.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2242840 + ... + 5589199.

It is an arithmetic number, because the mean of its divisors is an integer number (577299668400).

Almost surely, 2^{13104411014020} is an apocalyptic number.

13104411014020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104411014020 is an abundant number, since it is smaller than the sum of its proper divisors (14605973069180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104411014020 is a wasteful number, since it uses less digits than its factorization.

13104411014020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7832628 (or 7832626 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 13104411014020 its reverse (2041011440131), we get a palindrome (15145422454151).

The spelling of 13104411014020 in words is "thirteen trillion, one hundred four billion, four hundred eleven million, fourteen thousand, twenty".