Base | Representation |
---|---|
bin | 1011111010110001101111… |
… | …1010000101000111001111 |
3 | 1201101202210002210100121211 |
4 | 2332230123322011013033 |
5 | 3204200314314231343 |
6 | 43512030122435251 |
7 | 2521522403202403 |
oct | 276543372050717 |
9 | 51352702710554 |
10 | 13104413430223 |
11 | 41a2606828295 |
12 | 1577881662b27 |
13 | 740982950b1b |
14 | 334385299103 |
15 | 17ad210ae79d |
hex | beb1be851cf |
13104413430223 has 2 divisors, whose sum is σ = 13104413430224. Its totient is φ = 13104413430222.
The previous prime is 13104413430151. The next prime is 13104413430259. The reversal of 13104413430223 is 32203431440131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13104413430223 - 229 = 13103876559311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104413430523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552206715111 + 6552206715112.
It is an arithmetic number, because the mean of its divisors is an integer number (6552206715112).
Almost surely, 213104413430223 is an apocalyptic number.
13104413430223 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104413430223 is an equidigital number, since it uses as much as digits as its factorization.
13104413430223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13104413430223 its reverse (32203431440131), we get a palindrome (45307844870354).
The spelling of 13104413430223 in words is "thirteen trillion, one hundred four billion, four hundred thirteen million, four hundred thirty thousand, two hundred twenty-three".
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