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131044251502523 is a prime number
BaseRepresentation
bin11101110010111100011110…
…000011111000011110111011
3122011222201010012102221210202
4131302330132003320132323
5114134012111341040043
61142412521551432415
736413430500055422
oct3562743603703673
9564881105387722
10131044251502523
1138833611724a07
121284530682570b
13581755c672238
14245080b6b42b9
151023b65b9b1b8
hex772f1e0f87bb

131044251502523 has 2 divisors, whose sum is σ = 131044251502524. Its totient is φ = 131044251502522.

The previous prime is 131044251502511. The next prime is 131044251502553. The reversal of 131044251502523 is 325205152440131.

It is a weak prime.

It is an emirp because it is prime and its reverse (325205152440131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131044251502523 - 214 = 131044251486139 is a prime.

It is not a weakly prime, because it can be changed into another prime (131044251502553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522125751261 + 65522125751262.

It is an arithmetic number, because the mean of its divisors is an integer number (65522125751262).

Almost surely, 2131044251502523 is an apocalyptic number.

131044251502523 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044251502523 is an equidigital number, since it uses as much as digits as its factorization.

131044251502523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 131044251502523 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, five hundred two thousand, five hundred twenty-three".