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13104442513009 is a prime number
BaseRepresentation
bin1011111010110001110110…
…1001000001011001110001
31201101202212010111220201001
42332230131221001121301
53204200344240404014
643512033042042001
72521523205331021
oct276543551013161
951352763456631
1013104442513009
1141a2621191651
12157788b349301
13740988994483
143343890a9a81
1517ad23906974
hexbeb1da41671

13104442513009 has 2 divisors, whose sum is σ = 13104442513010. Its totient is φ = 13104442513008.

The previous prime is 13104442513007. The next prime is 13104442513027. The reversal of 13104442513009 is 90031524440131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10745100432784 + 2359342080225 = 3277972^2 + 1536015^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104442513009 - 21 = 13104442513007 is a prime.

Together with 13104442513007, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13104442513007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552221256504 + 6552221256505.

It is an arithmetic number, because the mean of its divisors is an integer number (6552221256505).

Almost surely, 213104442513009 is an apocalyptic number.

It is an amenable number.

13104442513009 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104442513009 is an equidigital number, since it uses as much as digits as its factorization.

13104442513009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 13104442513009 in words is "thirteen trillion, one hundred four billion, four hundred forty-two million, five hundred thirteen thousand, nine".