Base | Representation |
---|---|
bin | 1011111010110001110110… |
… | …1001000001011001110001 |
3 | 1201101202212010111220201001 |
4 | 2332230131221001121301 |
5 | 3204200344240404014 |
6 | 43512033042042001 |
7 | 2521523205331021 |
oct | 276543551013161 |
9 | 51352763456631 |
10 | 13104442513009 |
11 | 41a2621191651 |
12 | 157788b349301 |
13 | 740988994483 |
14 | 3343890a9a81 |
15 | 17ad23906974 |
hex | beb1da41671 |
13104442513009 has 2 divisors, whose sum is σ = 13104442513010. Its totient is φ = 13104442513008.
The previous prime is 13104442513007. The next prime is 13104442513027. The reversal of 13104442513009 is 90031524440131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10745100432784 + 2359342080225 = 3277972^2 + 1536015^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104442513009 - 21 = 13104442513007 is a prime.
Together with 13104442513007, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13104442513007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552221256504 + 6552221256505.
It is an arithmetic number, because the mean of its divisors is an integer number (6552221256505).
Almost surely, 213104442513009 is an apocalyptic number.
It is an amenable number.
13104442513009 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104442513009 is an equidigital number, since it uses as much as digits as its factorization.
13104442513009 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 13104442513009 in words is "thirteen trillion, one hundred four billion, four hundred forty-two million, five hundred thirteen thousand, nine".
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