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1310450141041 is a prime number
BaseRepresentation
bin10011000100011100111…
…010100100011101110001
311122021111112010121202221
4103010130322210131301
5132432300214003131
62442002410241041
7163451114261026
oct23043472443561
94567445117687
101310450141041
11465838a39898
12191b83126181
1396762130852
14475d740554d
152414b59d411
hex1311cea4771

1310450141041 has 2 divisors, whose sum is σ = 1310450141042. Its totient is φ = 1310450141040.

The previous prime is 1310450141029. The next prime is 1310450141069. The reversal of 1310450141041 is 1401410540131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 778622700816 + 531827440225 = 882396^2 + 729265^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310450141041 - 239 = 760694327153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310450140997 and 1310450141015.

It is not a weakly prime, because it can be changed into another prime (1310450141141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655225070520 + 655225070521.

It is an arithmetic number, because the mean of its divisors is an integer number (655225070521).

Almost surely, 21310450141041 is an apocalyptic number.

It is an amenable number.

1310450141041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310450141041 is an equidigital number, since it uses as much as digits as its factorization.

1310450141041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 1310450141041 its reverse (1401410540131), we get a palindrome (2711860681172).

The spelling of 1310450141041 in words is "one trillion, three hundred ten billion, four hundred fifty million, one hundred forty-one thousand, forty-one".