Base | Representation |
---|---|
bin | 11101110010111101011001… |
… | …101001111001100001010111 |
3 | 122011222210200212210011000111 |
4 | 131302331121221321201113 |
5 | 114134021133314331431 |
6 | 1142413205105223451 |
7 | 36413464330314004 |
oct | 3562753151714127 |
9 | 564883625704014 |
10 | 131045251323991 |
11 | 38833a85036644 |
12 | 12845545631b87 |
13 | 581768b849084 |
14 | 24508a43b68ab |
15 | 1023bc38447b1 |
hex | 772f59a79857 |
131045251323991 has 2 divisors, whose sum is σ = 131045251323992. Its totient is φ = 131045251323990.
The previous prime is 131045251323977. The next prime is 131045251324073. The reversal of 131045251323991 is 199323152540131.
It is a weak prime.
It is an emirp because it is prime and its reverse (199323152540131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131045251323991 - 233 = 131036661389399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131045251323941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522625661995 + 65522625661996.
It is an arithmetic number, because the mean of its divisors is an integer number (65522625661996).
Almost surely, 2131045251323991 is an apocalyptic number.
131045251323991 is a deficient number, since it is larger than the sum of its proper divisors (1).
131045251323991 is an equidigital number, since it uses as much as digits as its factorization.
131045251323991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 874800, while the sum is 49.
The spelling of 131045251323991 in words is "one hundred thirty-one trillion, forty-five billion, two hundred fifty-one million, three hundred twenty-three thousand, nine hundred ninety-one".
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