Base | Representation |
---|---|
bin | 11101110010111101011001… |
… | …110010001111010101101111 |
3 | 122011222210201000220020100201 |
4 | 131302331121302033111233 |
5 | 114134021134344314021 |
6 | 1142413205224134331 |
7 | 36413464355021464 |
oct | 3562753162172557 |
9 | 564883630806321 |
10 | 131045253510511 |
11 | 38833a8629a38a |
12 | 128455463073a7 |
13 | 581768c133382 |
14 | 24508a47c566b |
15 | 1023bc3b27591 |
hex | 772f59c8f56f |
131045253510511 has 2 divisors, whose sum is σ = 131045253510512. Its totient is φ = 131045253510510.
The previous prime is 131045253510419. The next prime is 131045253510551. The reversal of 131045253510511 is 115015352540131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131045253510511 - 29 = 131045253509999 is a prime.
It is a super-2 number, since 2×1310452535105112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131045253510551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522626755255 + 65522626755256.
It is an arithmetic number, because the mean of its divisors is an integer number (65522626755256).
Almost surely, 2131045253510511 is an apocalyptic number.
131045253510511 is a deficient number, since it is larger than the sum of its proper divisors (1).
131045253510511 is an equidigital number, since it uses as much as digits as its factorization.
131045253510511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45000, while the sum is 37.
The spelling of 131045253510511 in words is "one hundred thirty-one trillion, forty-five billion, two hundred fifty-three million, five hundred ten thousand, five hundred eleven".
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