Base | Representation |
---|---|
bin | 11101110010111101100010… |
… | …100001100011011110011011 |
3 | 122011222211002020210100112002 |
4 | 131302331202201203132123 |
5 | 114134021434413201413 |
6 | 1142413231542511215 |
7 | 36413501115206045 |
oct | 3562754241433633 |
9 | 564884066710462 |
10 | 131045400131483 |
11 | 38834051033942 |
12 | 1284558743550b |
13 | 58176b361b246 |
14 | 24508ba070a95 |
15 | 1023bd193a958 |
hex | 772f6286379b |
131045400131483 has 2 divisors, whose sum is σ = 131045400131484. Its totient is φ = 131045400131482.
The previous prime is 131045400131423. The next prime is 131045400131489. The reversal of 131045400131483 is 384131004540131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131045400131483 - 228 = 131045131696027 is a prime.
It is not a weakly prime, because it can be changed into another prime (131045400131489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522700065741 + 65522700065742.
It is an arithmetic number, because the mean of its divisors is an integer number (65522700065742).
Almost surely, 2131045400131483 is an apocalyptic number.
131045400131483 is a deficient number, since it is larger than the sum of its proper divisors (1).
131045400131483 is an equidigital number, since it uses as much as digits as its factorization.
131045400131483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 38.
The spelling of 131045400131483 in words is "one hundred thirty-one trillion, forty-five billion, four hundred million, one hundred thirty-one thousand, four hundred eighty-three".
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