Base | Representation |
---|---|
bin | 11101110010111101100010… |
… | …110001100000011010000110 |
3 | 122011222211002112122210210022 |
4 | 131302331202301200122012 |
5 | 114134021442001010342 |
6 | 1142413232212255142 |
7 | 36413501165563520 |
oct | 3562754261403206 |
9 | 564884075583708 |
10 | 131045404313222 |
11 | 3883405342a723 |
12 | 128455889114b2 |
13 | 58176b4453749 |
14 | 24508ba83ca10 |
15 | 1023bd1eb49d2 |
hex | 772f62c60686 |
131045404313222 has 32 divisors (see below), whose sum is σ = 224790935416320. Its totient is φ = 56126900272320.
The previous prime is 131045404313221. The next prime is 131045404313251. The reversal of 131045404313222 is 222313404540131.
It is a super-2 number, since 2×1310454043132222 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131045404313221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1435423397 + ... + 1435514687.
It is an arithmetic number, because the mean of its divisors is an integer number (7024716731760).
Almost surely, 2131045404313222 is an apocalyptic number.
131045404313222 is a deficient number, since it is larger than the sum of its proper divisors (93745531103098).
131045404313222 is a wasteful number, since it uses less digits than its factorization.
131045404313222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 154836.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 131045404313222 its reverse (222313404540131), we get a palindrome (353358808853353).
The spelling of 131045404313222 in words is "one hundred thirty-one trillion, forty-five billion, four hundred four million, three hundred thirteen thousand, two hundred twenty-two".
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