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13104650024149 is a prime number
BaseRepresentation
bin1011111010110010101000…
…0000100111010011010101
31201101210101120222120110211
42332230222000213103111
53204201310401233044
643512105413445421
72521531305210535
oct276545200472325
951353346876424
1013104650024149
1141a2718334862
121577928940871
137409bc97b528
143343a88854c5
1517ad36c46634
hexbeb2a0274d5

13104650024149 has 2 divisors, whose sum is σ = 13104650024150. Its totient is φ = 13104650024148.

The previous prime is 13104650024113. The next prime is 13104650024177. The reversal of 13104650024149 is 94142005640131.

13104650024149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10783460657124 + 2321189367025 = 3283818^2 + 1523545^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104650024149 - 219 = 13104649499861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104650024449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552325012074 + 6552325012075.

It is an arithmetic number, because the mean of its divisors is an integer number (6552325012075).

Almost surely, 213104650024149 is an apocalyptic number.

It is an amenable number.

13104650024149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104650024149 is an equidigital number, since it uses as much as digits as its factorization.

13104650024149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 40.

The spelling of 13104650024149 in words is "thirteen trillion, one hundred four billion, six hundred fifty million, twenty-four thousand, one hundred forty-nine".