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131048113028000 = 255374799580633
BaseRepresentation
bin11101110011000000000100…
…001110011011101110100000
3122012000002002022120202220212
4131303000010032123232200
5114134043013413344000
61142414401053353252
736413625256354250
oct3563000416335640
9565002068522825
10131048113028000
1138835213429183
1212846003a98828
135817a2669ba5c
142450a9649d960
151023cdebbbc35
hex77300439bba0

131048113028000 has 192 divisors, whose sum is σ = 375812532845568. Its totient is φ = 43974807091200.

The previous prime is 131048113027967. The next prime is 131048113028023. The reversal of 131048113028000 is 820311840131.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48474317 + ... + 51106316.

It is an arithmetic number, because the mean of its divisors is an integer number (1957356941904).

Almost surely, 2131048113028000 is an apocalyptic number.

131048113028000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131048113028000 is an abundant number, since it is smaller than the sum of its proper divisors (244764419817568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131048113028000 is an equidigital number, since it uses as much as digits as its factorization.

131048113028000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99580712 (or 99580694 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 32.

Adding to 131048113028000 its reverse (820311840131), we get a palindrome (131868424868131).

The spelling of 131048113028000 in words is "one hundred thirty-one trillion, forty-eight billion, one hundred thirteen million, twenty-eight thousand".