Search a number
-
+
1310493104653 is a prime number
BaseRepresentation
bin10011000100011111011…
…110011101101000001101
311122021121111222101202211
4103010133132131220031
5132432342213322103
62442010543150421
7163452145411255
oct23043736355015
94567544871684
101310493104653
11465860214007
12191b955a5411
139676acc42c5
14475dcdca965
152415023836d
hex1311f79da0d

1310493104653 has 2 divisors, whose sum is σ = 1310493104654. Its totient is φ = 1310493104652.

The previous prime is 1310493104621. The next prime is 1310493104671. The reversal of 1310493104653 is 3564013940131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1160366303209 + 150126801444 = 1077203^2 + 387462^2 .

It is an emirp because it is prime and its reverse (3564013940131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310493104653 - 25 = 1310493104621 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310493104603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655246552326 + 655246552327.

It is an arithmetic number, because the mean of its divisors is an integer number (655246552327).

Almost surely, 21310493104653 is an apocalyptic number.

It is an amenable number.

1310493104653 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310493104653 is an equidigital number, since it uses as much as digits as its factorization.

1310493104653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 40.

The spelling of 1310493104653 in words is "one trillion, three hundred ten billion, four hundred ninety-three million, one hundred four thousand, six hundred fifty-three".