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1310500345030 = 2517219294319139
BaseRepresentation
bin10011000100011111111…
…010000101010011000110
311122021122000121020200221
4103010133322011103012
5132432401042020110
62442011402254554
7163452264065242
oct23043772052306
94567560536627
101310500345030
11465864309898
12191b97ab745a
139676c65aa56
14475ddd53422
1524150bb87da
hex1311fe854c6

1310500345030 has 192 divisors, whose sum is σ = 2792265696000. Its totient is φ = 440763144192.

The previous prime is 1310500344997. The next prime is 1310500345031. The reversal of 1310500345030 is 305430050131.

It is a super-2 number, since 2×13105003450302 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310500344986 and 1310500345004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310500345031) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 68463201 + ... + 68482339.

It is an arithmetic number, because the mean of its divisors is an integer number (14543050500).

Almost surely, 21310500345030 is an apocalyptic number.

1310500345030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310500345030 is an abundant number, since it is smaller than the sum of its proper divisors (1481765350970).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310500345030 is a wasteful number, since it uses less digits than its factorization.

1310500345030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19271 (or 19254 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 1310500345030 its reverse (305430050131), we get a palindrome (1615930395161).

The spelling of 1310500345030 in words is "one trillion, three hundred ten billion, five hundred million, three hundred forty-five thousand, thirty".