1310500434130 has 8 divisors (see below), whose sum is σ = 2358900781452. Its totient is φ = 524200173648.

The previous prime is 1310500434101. The next prime is 1310500434137. The reversal of 1310500434130 is 314340050131.

It can be written as a sum of positive squares in 2 ways, for example, as 1245185942641 + 65314491489 = 1115879^2 + 255567^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1310500434130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310500434095 and 1310500434104.

It is not an unprimeable number, because it can be changed into a prime (1310500434137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65525021697 + ... + 65525021716.

Almost surely, 2^{1310500434130} is an apocalyptic number.

1310500434130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310500434130 is a deficient number, since it is larger than the sum of its proper divisors (1048400347322).

1310500434130 is a wasteful number, since it uses less digits than its factorization.

1310500434130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131050043420.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 1310500434130 its reverse (314340050131), we get a palindrome (1624840484261).

The spelling of 1310500434130 in words is "one trillion, three hundred ten billion, five hundred million, four hundred thirty-four thousand, one hundred thirty".