13105024213441 has 2 divisors, whose sum is σ = 13105024213442. Its totient is φ = 13105024213440.

The previous prime is 13105024213427. The next prime is 13105024213469. The reversal of 13105024213441 is 14431242050131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12226183587216 + 878840626225 = 3496596^2 + 937465^2 .

It is a cyclic number.

It is not a de Polignac number, because 13105024213441 - 2¹¹ = 13105024211393 is a prime.

It is not a weakly prime, because it can be changed into another prime (13105022213441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552512106720 + 6552512106721.

It is an arithmetic number, because the mean of its divisors is an integer number (6552512106721).

Almost surely, 2^{13105024213441} is an apocalyptic number.

It is an amenable number.

13105024213441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105024213441 is an equidigital number, since it uses as much as digits as its factorization.

13105024213441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 13105024213441 its reverse (14431242050131), we get a palindrome (27536266263572).

The spelling of 13105024213441 in words is "thirteen trillion, one hundred five billion, twenty-four million, two hundred thirteen thousand, four hundred forty-one".