13105042002501 has 4 divisors (see below), whose sum is σ = 17473389336672. Its totient is φ = 8736694668332.

The previous prime is 13105042002473. The next prime is 13105042002517. The reversal of 13105042002501 is 10520024050131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13105042002501 is a prime.

It is a super-3 number, since 3×13105042002501³ (a number of 40 digits) contains 333 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105042002901) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2184173667081 + ... + 2184173667086.

It is an arithmetic number, because the mean of its divisors is an integer number (4368347334168).

Almost surely, 2^{13105042002501} is an apocalyptic number.

It is an amenable number.

13105042002501 is a deficient number, since it is larger than the sum of its proper divisors (4368347334171).

13105042002501 is an equidigital number, since it uses as much as digits as its factorization.

13105042002501 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4368347334170.

The product of its (nonzero) digits is 1200, while the sum is 24.

Adding to 13105042002501 its reverse (10520024050131), we get a palindrome (23625066052632).

The spelling of 13105042002501 in words is "thirteen trillion, one hundred five billion, forty-two million, two thousand, five hundred one".