Base | Representation |
---|---|
bin | 11101110011000100101110… |
… | …000101101110100010100010 |
3 | 122012000112222120221100100220 |
4 | 131303010232011232202202 |
5 | 114134133232222344010 |
6 | 1142420545011423510 |
7 | 36414163150063104 |
oct | 3563045605564242 |
9 | 565015876840326 |
10 | 131053110356130 |
11 | 38837348280826 |
12 | 12846b795b4b96 |
13 | 5818341b03451 |
14 | 245100c067574 |
15 | 1023ed3796970 |
hex | 77312e16e8a2 |
131053110356130 has 16 divisors (see below), whose sum is σ = 314527464854784. Its totient is φ = 34947496094960.
The previous prime is 131053110356087. The next prime is 131053110356213. The reversal of 131053110356130 is 31653011350131.
It is a junction number, because it is equal to n+sod(n) for n = 131053110356091 and 131053110356100.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2184218505906 + ... + 2184218505965.
It is an arithmetic number, because the mean of its divisors is an integer number (19657966553424).
Almost surely, 2131053110356130 is an apocalyptic number.
131053110356130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131053110356130 is an abundant number, since it is smaller than the sum of its proper divisors (183474354498654).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131053110356130 is a wasteful number, since it uses less digits than its factorization.
131053110356130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4368437011881.
The product of its (nonzero) digits is 12150, while the sum is 33.
The spelling of 131053110356130 in words is "one hundred thirty-one trillion, fifty-three billion, one hundred ten million, three hundred fifty-six thousand, one hundred thirty".
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