Base | Representation |
---|---|
bin | 10011000100100010000… |
… | …011011001111010011101 |
3 | 11122021201112100010220101 |
4 | 103010202003121322131 |
5 | 132432434300440242 |
6 | 2442015130021101 |
7 | 163453212055204 |
oct | 23044203317235 |
9 | 4567645303811 |
10 | 1310536343197 |
11 | 465882666844 |
12 | 191ba7b77791 |
13 | 96776c52c43 |
14 | 47604a4423b |
15 | 24153e299b7 |
hex | 131220d9e9d |
1310536343197 has 2 divisors, whose sum is σ = 1310536343198. Its totient is φ = 1310536343196.
The previous prime is 1310536343143. The next prime is 1310536343269. The reversal of 1310536343197 is 7913436350131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1308710832121 + 1825511076 = 1143989^2 + 42726^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310536343197 - 231 = 1308388859549 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310536383197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655268171598 + 655268171599.
It is an arithmetic number, because the mean of its divisors is an integer number (655268171599).
Almost surely, 21310536343197 is an apocalyptic number.
It is an amenable number.
1310536343197 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310536343197 is an equidigital number, since it uses as much as digits as its factorization.
1310536343197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 612360, while the sum is 46.
The spelling of 1310536343197 in words is "one trillion, three hundred ten billion, five hundred thirty-six million, three hundred forty-three thousand, one hundred ninety-seven".
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