13105403311438 has 4 divisors (see below), whose sum is σ = 19658104967160. Its totient is φ = 6552701655718.

The previous prime is 13105403311423. The next prime is 13105403311439. The reversal of 13105403311438 is 83411330450131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13105403311397 and 13105403311406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105403311439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276350827858 + ... + 3276350827861.

It is an arithmetic number, because the mean of its divisors is an integer number (4914526241790).

Almost surely, 2^{13105403311438} is an apocalyptic number.

13105403311438 is a deficient number, since it is larger than the sum of its proper divisors (6552701655722).

13105403311438 is an equidigital number, since it uses as much as digits as its factorization.

13105403311438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6552701655721.

The product of its (nonzero) digits is 51840, while the sum is 37.

Adding to 13105403311438 its reverse (83411330450131), we get a palindrome (96516733761569).

The spelling of 13105403311438 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred thirty-eight".