Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010001011010101001111 |
3 | 1201101212100002102112101002 |
4 | 2332231112322023111033 |
5 | 3204204331221431224 |
6 | 43512312243210515 |
7 | 2521556053100435 |
oct | 276552672132517 |
9 | 51355302375332 |
10 | 13105403311439 |
11 | 41a2a7456a73a |
12 | 1577ab9076a3b |
13 | 740aaca5735a |
14 | 33443a930d55 |
15 | 17ad7ce429ae |
hex | beb56e8b54f |
13105403311439 has 2 divisors, whose sum is σ = 13105403311440. Its totient is φ = 13105403311438.
The previous prime is 13105403311423. The next prime is 13105403311453. The reversal of 13105403311439 is 93411330450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13105403311439 - 24 = 13105403311423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105403311459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552701655719 + 6552701655720.
It is an arithmetic number, because the mean of its divisors is an integer number (6552701655720).
Almost surely, 213105403311439 is an apocalyptic number.
13105403311439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105403311439 is an equidigital number, since it uses as much as digits as its factorization.
13105403311439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 38.
The spelling of 13105403311439 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred thirty-nine".
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