13105405521401 has 2 divisors, whose sum is σ = 13105405521402. Its totient is φ = 13105405521400.

The previous prime is 13105405521287. The next prime is 13105405521421. The reversal of 13105405521401 is 10412550450131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12627753138025 + 477652383376 = 3553555^2 + 691124^2 .

It is an emirp because it is prime and its reverse (10412550450131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13105405521401 is a prime.

It is a super-3 number, since 3×13105405521401³ (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13105405521421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702760700 + 6552702760701.

It is an arithmetic number, because the mean of its divisors is an integer number (6552702760701).

Almost surely, 2^{13105405521401} is an apocalyptic number.

It is an amenable number.

13105405521401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105405521401 is an equidigital number, since it uses as much as digits as its factorization.

13105405521401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 13105405521401 its reverse (10412550450131), we get a palindrome (23517955971532).

The spelling of 13105405521401 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty-one thousand, four hundred one".