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13105412022055 = 52621082404411
BaseRepresentation
bin1011111010110101011101…
…1011011001111100100111
31201101212100200211002002111
42332231113123121330213
53204204340434201210
643512313154021451
72521556220120013
oct276552733317447
951355320732074
1013105412022055
1141a2a7947a0a1
121577abbb77887
13740ab17b7072
1433443bb5b543
1517ad7dab388a
hexbeb576d9f27

13105412022055 has 4 divisors (see below), whose sum is σ = 15726494426472. Its totient is φ = 10484329617640.

The previous prime is 13105412022011. The next prime is 13105412022071. The reversal of 13105412022055 is 55022021450131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13105412022055 - 29 = 13105412021543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310541202201 + ... + 1310541202210.

It is an arithmetic number, because the mean of its divisors is an integer number (3931623606618).

Almost surely, 213105412022055 is an apocalyptic number.

13105412022055 is a deficient number, since it is larger than the sum of its proper divisors (2621082404417).

13105412022055 is an equidigital number, since it uses as much as digits as its factorization.

13105412022055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2621082404416.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 13105412022055 its reverse (55022021450131), we get a palindrome (68127433472186).

The spelling of 13105412022055 in words is "thirteen trillion, one hundred five billion, four hundred twelve million, twenty-two thousand, fifty-five".

Divisors: 1 5 2621082404411 13105412022055