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13105412021543 is a prime number
BaseRepresentation
bin1011111010110101011101…
…1011011001110100100111
31201101212100200211001101112
42332231113123121310213
53204204340434142133
643512313154015235
72521556220115352
oct276552733316447
951355320731345
1013105412021543
1141a2a79479776
121577abbb7751b
13740ab17b6a6a
1433443bb5b299
1517ad7dab3648
hexbeb576d9d27

13105412021543 has 2 divisors, whose sum is σ = 13105412021544. Its totient is φ = 13105412021542.

The previous prime is 13105412021491. The next prime is 13105412021549. The reversal of 13105412021543 is 34512021450131.

It is a strong prime.

It is an emirp because it is prime and its reverse (34512021450131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13105412021543 - 214 = 13105412005159 is a prime.

It is a super-2 number, since 2×131054120215432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13105412021549) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552706010771 + 6552706010772.

It is an arithmetic number, because the mean of its divisors is an integer number (6552706010772).

Almost surely, 213105412021543 is an apocalyptic number.

13105412021543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105412021543 is an equidigital number, since it uses as much as digits as its factorization.

13105412021543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 13105412021543 its reverse (34512021450131), we get a palindrome (47617433471674).

The spelling of 13105412021543 in words is "thirteen trillion, one hundred five billion, four hundred twelve million, twenty-one thousand, five hundred forty-three".