Base | Representation |
---|---|
bin | 1011111010110101011101… |
… | …1011111001111100010011 |
3 | 1201101212100201001201212021 |
4 | 2332231113123321330103 |
5 | 3204204341002344412 |
6 | 43512313200512311 |
7 | 2521556221204051 |
oct | 276552733717423 |
9 | 51355321051767 |
10 | 13105412153107 |
11 | 41a2a795595aa |
12 | 1577b0001b697 |
13 | 740ab1831901 |
14 | 33443bb931d1 |
15 | 17ad7dadc607 |
hex | beb576f9f13 |
13105412153107 has 2 divisors, whose sum is σ = 13105412153108. Its totient is φ = 13105412153106.
The previous prime is 13105412153089. The next prime is 13105412153117. The reversal of 13105412153107 is 70135121450131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13105412153107 is a prime.
It is not a weakly prime, because it can be changed into another prime (13105412153117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552706076553 + 6552706076554.
It is an arithmetic number, because the mean of its divisors is an integer number (6552706076554).
Almost surely, 213105412153107 is an apocalyptic number.
13105412153107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105412153107 is an equidigital number, since it uses as much as digits as its factorization.
13105412153107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12600, while the sum is 34.
The spelling of 13105412153107 in words is "thirteen trillion, one hundred five billion, four hundred twelve million, one hundred fifty-three thousand, one hundred seven".
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