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1310541505001 is a prime number
BaseRepresentation
bin10011000100100010010…
…111000110000111101001
311122021201220001101120022
4103010202113012013221
5132432442111130001
62442015432410225
7163453303664201
oct23044227060751
94567656041508
101310541505001
114658855719a3
12191ba9846975
139677803c571
14476055c9401
15241545e911b
hex131225c61e9

1310541505001 has 2 divisors, whose sum is σ = 1310541505002. Its totient is φ = 1310541505000.

The previous prime is 1310541504983. The next prime is 1310541505027. The reversal of 1310541505001 is 1005051450131.

It is an a-pointer prime, because the next prime (1310541505027) can be obtained adding 1310541505001 to its sum of digits (26).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 937122738601 + 373418766400 = 968051^2 + 611080^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310541505001 - 210 = 1310541503977 is a prime.

It is a super-2 number, since 2×13105415050012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1310541502001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655270752500 + 655270752501.

It is an arithmetic number, because the mean of its divisors is an integer number (655270752501).

Almost surely, 21310541505001 is an apocalyptic number.

It is an amenable number.

1310541505001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310541505001 is an equidigital number, since it uses as much as digits as its factorization.

1310541505001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1500, while the sum is 26.

Adding to 1310541505001 its reverse (1005051450131), we get a palindrome (2315592955132).

The spelling of 1310541505001 in words is "one trillion, three hundred ten billion, five hundred forty-one million, five hundred five thousand, one".