Base | Representation |
---|---|
bin | 11101110011000101111000… |
… | …001110010011110011100011 |
3 | 122012000200012021022002111222 |
4 | 131303011320032103303203 |
5 | 114134143304123314112 |
6 | 1142421312241525255 |
7 | 36414236031643421 |
oct | 3563057016236343 |
9 | 565020167262458 |
10 | 131054354119907 |
11 | 38837926358979 |
12 | 1284726604382b |
13 | 58184ac6ab64a |
14 | 24510c930a111 |
15 | 1024057a79372 |
hex | 773178393ce3 |
131054354119907 has 2 divisors, whose sum is σ = 131054354119908. Its totient is φ = 131054354119906.
The previous prime is 131054354119879. The next prime is 131054354119957. The reversal of 131054354119907 is 709911453450131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131054354119907 - 244 = 113462168075491 is a prime.
It is not a weakly prime, because it can be changed into another prime (131054354119957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65527177059953 + 65527177059954.
It is an arithmetic number, because the mean of its divisors is an integer number (65527177059954).
Almost surely, 2131054354119907 is an apocalyptic number.
131054354119907 is a deficient number, since it is larger than the sum of its proper divisors (1).
131054354119907 is an equidigital number, since it uses as much as digits as its factorization.
131054354119907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2041200, while the sum is 53.
The spelling of 131054354119907 in words is "one hundred thirty-one trillion, fifty-four billion, three hundred fifty-four million, one hundred nineteen thousand, nine hundred seven".
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