Base | Representation |
---|---|
bin | 11101110011000101111100… |
… | …110111100011110000010000 |
3 | 122012000200101200220221112102 |
4 | 131303011330313203300100 |
5 | 114134143434100321000 |
6 | 1142421324104015532 |
7 | 36414240666163505 |
oct | 3563057467436020 |
9 | 565020350827472 |
10 | 131054432042000 |
11 | 3883796633a9a5 |
12 | 128472881615a8 |
13 | 58184c2891cac |
14 | 24510d57d14ac |
15 | 102405e81c3d5 |
hex | 77317cde3c10 |
131054432042000 has 160 divisors (see below), whose sum is σ = 325094054148864. Its totient is φ = 51068290944000.
The previous prime is 131054432041927. The next prime is 131054432042021. The reversal of 131054432042000 is 240234450131.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 54835997 + ... + 57176003.
Almost surely, 2131054432042000 is an apocalyptic number.
131054432042000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131054432042000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162547027074432).
131054432042000 is an abundant number, since it is smaller than the sum of its proper divisors (194039622106864).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131054432042000 is a wasteful number, since it uses less digits than its factorization.
131054432042000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2340754 (or 2340738 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 131054432042000 its reverse (240234450131), we get a palindrome (131294666492131).
The spelling of 131054432042000 in words is "one hundred thirty-one trillion, fifty-four billion, four hundred thirty-two million, forty-two thousand".
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