Base | Representation |
---|---|
bin | 111101000001110110… |
… | …0000001100100011111 |
3 | 110112021200110021002210 |
4 | 1322003230001210133 |
5 | 4121401420444233 |
6 | 140112443451503 |
7 | 12316514543406 |
oct | 1720354014437 |
9 | 415250407083 |
10 | 131058374943 |
11 | 50644043971 |
12 | 21497226b93 |
13 | c4882400b2 |
14 | 64b3c9063d |
15 | 3620c26163 |
hex | 1e83b0191f |
131058374943 has 4 divisors (see below), whose sum is σ = 174744499928. Its totient is φ = 87372249960.
The previous prime is 131058374879. The next prime is 131058374947. The reversal of 131058374943 is 349473850131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131058374943 - 26 = 131058374879 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131058374892 and 131058374901.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131058374947) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21843062488 + ... + 21843062493.
It is an arithmetic number, because the mean of its divisors is an integer number (43686124982).
Almost surely, 2131058374943 is an apocalyptic number.
131058374943 is a deficient number, since it is larger than the sum of its proper divisors (43686124985).
131058374943 is an equidigital number, since it uses as much as digits as its factorization.
131058374943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43686124984.
The product of its (nonzero) digits is 1088640, while the sum is 48.
The spelling of 131058374943 in words is "one hundred thirty-one billion, fifty-eight million, three hundred seventy-four thousand, nine hundred forty-three".
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