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131058374943 = 343686124981
BaseRepresentation
bin111101000001110110…
…0000001100100011111
3110112021200110021002210
41322003230001210133
54121401420444233
6140112443451503
712316514543406
oct1720354014437
9415250407083
10131058374943
1150644043971
1221497226b93
13c4882400b2
1464b3c9063d
153620c26163
hex1e83b0191f

131058374943 has 4 divisors (see below), whose sum is σ = 174744499928. Its totient is φ = 87372249960.

The previous prime is 131058374879. The next prime is 131058374947. The reversal of 131058374943 is 349473850131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131058374943 - 26 = 131058374879 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131058374892 and 131058374901.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131058374947) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21843062488 + ... + 21843062493.

It is an arithmetic number, because the mean of its divisors is an integer number (43686124982).

Almost surely, 2131058374943 is an apocalyptic number.

131058374943 is a deficient number, since it is larger than the sum of its proper divisors (43686124985).

131058374943 is an equidigital number, since it uses as much as digits as its factorization.

131058374943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43686124984.

The product of its (nonzero) digits is 1088640, while the sum is 48.

The spelling of 131058374943 in words is "one hundred thirty-one billion, fifty-eight million, three hundred seventy-four thousand, nine hundred forty-three".

Divisors: 1 3 43686124981 131058374943