Base | Representation |
---|---|
bin | 111101000001110110… |
… | …0000001100100100011 |
3 | 110112021200110021002221 |
4 | 1322003230001210203 |
5 | 4121401420444242 |
6 | 140112443451511 |
7 | 12316514543413 |
oct | 1720354014443 |
9 | 415250407087 |
10 | 131058374947 |
11 | 50644043975 |
12 | 21497226b97 |
13 | c4882400b6 |
14 | 64b3c90643 |
15 | 3620c26167 |
hex | 1e83b01923 |
131058374947 has 2 divisors, whose sum is σ = 131058374948. Its totient is φ = 131058374946.
The previous prime is 131058374879. The next prime is 131058374957. The reversal of 131058374947 is 749473850131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131058374947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131058374894 and 131058374903.
It is not a weakly prime, because it can be changed into another prime (131058374957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65529187473 + 65529187474.
It is an arithmetic number, because the mean of its divisors is an integer number (65529187474).
Almost surely, 2131058374947 is an apocalyptic number.
131058374947 is a deficient number, since it is larger than the sum of its proper divisors (1).
131058374947 is an equidigital number, since it uses as much as digits as its factorization.
131058374947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2540160, while the sum is 52.
The spelling of 131058374947 in words is "one hundred thirty-one billion, fifty-eight million, three hundred seventy-four thousand, nine hundred forty-seven".
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