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131065481 is a prime number
BaseRepresentation
bin1111100111111…
…10011010001001
3100010121211001002
413303332122021
5232023043411
621001104345
73151016051
oct763763211
9303554032
10131065481
1167a8a488
1237a880b5
13211cc751
141359a561
15b78e33b
hex7cfe689

131065481 has 2 divisors, whose sum is σ = 131065482. Its totient is φ = 131065480.

The previous prime is 131065399. The next prime is 131065483. The reversal of 131065481 is 184560131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82065481 + 49000000 = 9059^2 + 7000^2 .

It is a cyclic number.

It is not a de Polignac number, because 131065481 - 214 = 131049097 is a prime.

It is a super-2 number, since 2×1310654812 = 34356320619522722, which contains 22 as substring.

Together with 131065483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131065483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65532740 + 65532741.

It is an arithmetic number, because the mean of its divisors is an integer number (65532741).

Almost surely, 2131065481 is an apocalyptic number.

It is an amenable number.

131065481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131065481 is an equidigital number, since it uses as much as digits as its factorization.

131065481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 29.

The square root of 131065481 is about 11448.3833356505. The cubic root of 131065481 is about 507.9599150486.

The spelling of 131065481 in words is "one hundred thirty-one million, sixty-five thousand, four hundred eighty-one".