Base | Representation |
---|---|
bin | 11000011010011100… |
… | …11110101010001011 |
3 | 1020211102202111021212 |
4 | 30031032132222023 |
5 | 203320320120131 |
6 | 10004324123335 |
7 | 642540654443 |
oct | 141516365213 |
9 | 36742674255 |
10 | 13106801291 |
11 | 56164a1891 |
12 | 265953654b |
13 | 130b55712c |
14 | 8c4a0b123 |
15 | 51a9eba2b |
hex | 30d39ea8b |
13106801291 has 2 divisors, whose sum is σ = 13106801292. Its totient is φ = 13106801290.
The previous prime is 13106801273. The next prime is 13106801299. The reversal of 13106801291 is 19210860131.
It is a strong prime.
It is an emirp because it is prime and its reverse (19210860131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13106801291 - 222 = 13102606987 is a prime.
It is not a weakly prime, because it can be changed into another prime (13106801299) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6553400645 + 6553400646.
It is an arithmetic number, because the mean of its divisors is an integer number (6553400646).
Almost surely, 213106801291 is an apocalyptic number.
13106801291 is a deficient number, since it is larger than the sum of its proper divisors (1).
13106801291 is an equidigital number, since it uses as much as digits as its factorization.
13106801291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 32.
The spelling of 13106801291 in words is "thirteen billion, one hundred six million, eight hundred one thousand, two hundred ninety-one".
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