Search a number
-
+
1310963813 is a prime number
BaseRepresentation
bin100111000100011…
…1011100001100101
310101100210212021022
41032020323201211
510141101320223
6334030300525
744326002635
oct11610734145
93340725238
101310963813
11613006575
12307057745
1317b7a6443
14c61766c5
157a158ac8
hex4e23b865

1310963813 has 2 divisors, whose sum is σ = 1310963814. Its totient is φ = 1310963812.

The previous prime is 1310963803. The next prime is 1310963831. The reversal of 1310963813 is 3183690131.

Together with next prime (1310963831) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1275418369 + 35545444 = 35713^2 + 5962^2 .

It is an emirp because it is prime and its reverse (3183690131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310963813 - 210 = 1310962789 is a prime.

It is a super-2 number, since 2×13109638132 = 3437252237990997938, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310963803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655481906 + 655481907.

It is an arithmetic number, because the mean of its divisors is an integer number (655481907).

Almost surely, 21310963813 is an apocalyptic number.

It is an amenable number.

1310963813 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310963813 is an equidigital number, since it uses as much as digits as its factorization.

1310963813 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664, while the sum is 35.

The square root of 1310963813 is about 36207.2342633347. The cubic root of 1310963813 is about 1094.4524588219.

The spelling of 1310963813 in words is "one billion, three hundred ten million, nine hundred sixty-three thousand, eight hundred thirteen".