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13110004255 = 523114000037
BaseRepresentation
bin11000011010110101…
…01100101000011111
31020211122210012221011
430031122230220133
5203322130114010
610004520520051
7642610124515
oct141532545037
936748705834
1013110004255
11561828a267
12265a620027
13130c108c8a
148c52024b5
1551ae30a8a
hex30d6aca1f

13110004255 has 8 divisors (see below), whose sum is σ = 16416005472. Its totient is φ = 10032003168.

The previous prime is 13110004249. The next prime is 13110004261. The reversal of 13110004255 is 55240001131.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (13110004249) and next prime (13110004261).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13110004255 - 215 = 13109971487 is a prime.

It is a super-2 number, since 2×131100042552 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56999904 + ... + 57000133.

It is an arithmetic number, because the mean of its divisors is an integer number (2052000684).

Almost surely, 213110004255 is an apocalyptic number.

13110004255 is a deficient number, since it is larger than the sum of its proper divisors (3306001217).

13110004255 is a wasteful number, since it uses less digits than its factorization.

13110004255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114000065.

The product of its (nonzero) digits is 600, while the sum is 22.

Adding to 13110004255 its reverse (55240001131), we get a palindrome (68350005386).

The spelling of 13110004255 in words is "thirteen billion, one hundred ten million, four thousand, two hundred fifty-five".

Divisors: 1 5 23 115 114000037 570000185 2622000851 13110004255