13110004261 has 2 divisors, whose sum is σ = 13110004262. Its totient is φ = 13110004260.

The previous prime is 13110004249. The next prime is 13110004363. The reversal of 13110004261 is 16240001131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10561672900 + 2548331361 = 102770^2 + 50481^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110004261 is a prime.

It is a super-2 number, since 2×13110004261² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110074261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555002130 + 6555002131.

It is an arithmetic number, because the mean of its divisors is an integer number (6555002131).

Almost surely, 2^13110004261 is an apocalyptic number.

It is an amenable number.

13110004261 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110004261 is an equidigital number, since it uses as much as digits as its factorization.

13110004261 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13110004261 its reverse (16240001131), we get a palindrome (29350005392).

The spelling of 13110004261 in words is "thirteen billion, one hundred ten million, four thousand, two hundred sixty-one".