Base | Representation |
---|---|
bin | 111101000011000101… |
… | …1100111100001100111 |
3 | 110112101121011202210121 |
4 | 1322012023213201213 |
5 | 4121443123230203 |
6 | 140120540302411 |
7 | 12320533260325 |
oct | 1720613474147 |
9 | 415347152717 |
10 | 131100211303 |
11 | 50665719176 |
12 | 214a9241a07 |
13 | c493aca739 |
14 | 64b9660d15 |
15 | 362473c0bd |
hex | 1e862e7867 |
131100211303 has 2 divisors, whose sum is σ = 131100211304. Its totient is φ = 131100211302.
The previous prime is 131100211241. The next prime is 131100211327. The reversal of 131100211303 is 303112001131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131100211303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131100211343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550105651 + 65550105652.
It is an arithmetic number, because the mean of its divisors is an integer number (65550105652).
Almost surely, 2131100211303 is an apocalyptic number.
131100211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131100211303 is an equidigital number, since it uses as much as digits as its factorization.
131100211303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131100211303 its reverse (303112001131), we get a palindrome (434212212434).
The spelling of 131100211303 in words is "one hundred thirty-one billion, one hundred million, two hundred eleven thousand, three hundred three".
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