13110034134340 has 72 divisors (see below), whose sum is σ = 32589227968920. Its totient is φ = 4400570887680.

The previous prime is 13110034134331. The next prime is 13110034134349. The reversal of 13110034134340 is 4343143001131.

It is an interprime number because it is at equal distance from previous prime (13110034134331) and next prime (13110034134349).

It can be written as a sum of positive squares in 4 ways, for example, as 962062799104 + 12147971335236 = 980848^2 + 3485394^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13110034134299 and 13110034134308.

It is not an unprimeable number, because it can be changed into a prime (13110034134349) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 208328905 + ... + 208391824.

It is an arithmetic number, because the mean of its divisors is an integer number (452628166235).

Almost surely, 2^{13110034134340} is an apocalyptic number.

13110034134340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13110034134340 is an abundant number, since it is smaller than the sum of its proper divisors (19479193834580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110034134340 is a wasteful number, since it uses less digits than its factorization.

13110034134340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 416720773 (or 416720760 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13110034134340 its reverse (4343143001131), we get a palindrome (17453177135471).

The spelling of 13110034134340 in words is "thirteen trillion, one hundred ten billion, thirty-four million, one hundred thirty-four thousand, three hundred forty".