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13110084241 is a prime number
BaseRepresentation
bin11000011010110110…
…00000001010010001
31020211122221021122121
430031123000022101
5203322140143431
610004522334241
7642610606642
oct141533001221
936748837577
1013110084241
115618334371
12265a65a381
13130c1364c7
148c52236c9
1551ae49611
hex30d6c0291

13110084241 has 2 divisors, whose sum is σ = 13110084242. Its totient is φ = 13110084240.

The previous prime is 13110084223. The next prime is 13110084269. The reversal of 13110084241 is 14248001131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12126634641 + 983449600 = 110121^2 + 31360^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110084241 - 25 = 13110084209 is a prime.

It is a super-2 number, since 2×131100842412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13110081241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555042120 + 6555042121.

It is an arithmetic number, because the mean of its divisors is an integer number (6555042121).

Almost surely, 213110084241 is an apocalyptic number.

It is an amenable number.

13110084241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110084241 is an equidigital number, since it uses as much as digits as its factorization.

13110084241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 13110084241 its reverse (14248001131), we get a palindrome (27358085372).

The spelling of 13110084241 in words is "thirteen billion, one hundred ten million, eighty-four thousand, two hundred forty-one".