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131101004010240 = 28335111380724977
BaseRepresentation
bin11101110011110001010100…
…110001100001001100000000
3122012012010121101022001122000
4131303301110301201030000
5114140424324011311430
61142454545250544000
736420510044321535
oct3563612461411400
9565163541261560
10131101004010240
1138855694a70a50
1212854304b98000
13581ca05372a54
142453472b38d8c
15102538826de60
hex773c54c61300

131101004010240 has 576 divisors, whose sum is σ = 507576874936320. Its totient is φ = 31778487336960.

The previous prime is 131101004010227. The next prime is 131101004010257. The reversal of 131101004010240 is 42010400101131.

131101004010240 is a `hidden beast` number, since 1 + 3 + 1 + 10 + 10 + 0 + 401 + 0 + 240 = 666.

It is a tau number, because it is divible by the number of its divisors (576).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5248856632 + ... + 5248881608.

It is an arithmetic number, because the mean of its divisors is an integer number (881209852320).

Almost surely, 2131101004010240 is an apocalyptic number.

131101004010240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131101004010240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (253788437468160).

131101004010240 is an abundant number, since it is smaller than the sum of its proper divisors (376475870926080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131101004010240 is a wasteful number, since it uses less digits than its factorization.

131101004010240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38825 (or 38805 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 131101004010240 its reverse (42010400101131), we get a palindrome (173111404111371).

The spelling of 131101004010240 in words is "one hundred thirty-one trillion, one hundred one billion, four million, ten thousand, two hundred forty".