13110102401441 has 2 divisors, whose sum is σ = 13110102401442. Its totient is φ = 13110102401440.

The previous prime is 13110102401413. The next prime is 13110102401443. The reversal of 13110102401441 is 14410420101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6846700224400 + 6263402177041 = 2616620^2 + 2502679^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110102401441 - 2³⁸ = 12835224494497 is a prime.

Together with 13110102401443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13110102401443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555051200720 + 6555051200721.

It is an arithmetic number, because the mean of its divisors is an integer number (6555051200721).

Almost surely, 2^{13110102401441} is an apocalyptic number.

It is an amenable number.

13110102401441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110102401441 is an equidigital number, since it uses as much as digits as its factorization.

13110102401441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 13110102401441 its reverse (14410420101131), we get a palindrome (27520522502572).

The spelling of 13110102401441 in words is "thirteen trillion, one hundred ten billion, one hundred two million, four hundred one thousand, four hundred forty-one".