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13110110431447 is a prime number
BaseRepresentation
bin1011111011000110111101…
…1110011010100011010111
31201102022111010201000010011
42332301233132122203113
53204244001232301242
643514411313141051
72522113521001411
oct276615736324327
951368433630104
1013110110431447
1141a4a6a616667
1215789b155a787
1374138000bb73
14334765b539b1
1517b0562e4d17
hexbec6f79a8d7

13110110431447 has 2 divisors, whose sum is σ = 13110110431448. Its totient is φ = 13110110431446.

The previous prime is 13110110431373. The next prime is 13110110431573. The reversal of 13110110431447 is 74413401101131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110110431447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110110437447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555055215723 + 6555055215724.

It is an arithmetic number, because the mean of its divisors is an integer number (6555055215724).

Almost surely, 213110110431447 is an apocalyptic number.

13110110431447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110110431447 is an equidigital number, since it uses as much as digits as its factorization.

13110110431447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 13110110431447 its reverse (74413401101131), we get a palindrome (87523511532578).

The spelling of 13110110431447 in words is "thirteen trillion, one hundred ten billion, one hundred ten million, four hundred thirty-one thousand, four hundred forty-seven".