Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0001011011111001101000 |
3 | 1201102022111012012020110202 |
4 | 2332301233201123321220 |
5 | 3204244001433122100 |
6 | 43514411342131332 |
7 | 2522113530510332 |
oct | 276615741337150 |
9 | 51368435166422 |
10 | 13110111223400 |
11 | 41a4a70007674 |
12 | 15789b1880b48 |
13 | 741380228489 |
14 | 334765cbc452 |
15 | 17b0563ee7d5 |
hex | bec6f85be68 |
13110111223400 has 48 divisors (see below), whose sum is σ = 31806269848800. Its totient is φ = 5016042553280.
The previous prime is 13110111223379. The next prime is 13110111223453. The reversal of 13110111223400 is 432211101131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1425007490 + ... + 1425016689.
It is an arithmetic number, because the mean of its divisors is an integer number (662630621850).
Almost surely, 213110111223400 is an apocalyptic number.
13110111223400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13110111223400 is an abundant number, since it is smaller than the sum of its proper divisors (18696158625400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110111223400 is a wasteful number, since it uses less digits than its factorization.
13110111223400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2850024218 (or 2850024209 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 13110111223400 its reverse (432211101131), we get a palindrome (13542322324531).
The spelling of 13110111223400 in words is "thirteen trillion, one hundred ten billion, one hundred eleven million, two hundred twenty-three thousand, four hundred".
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